WebThe Answer is 8 grams of NaOH. Some pre-requisite knowledge to solve the question are: Molar mass of NaOH = 40u Molarity = Mass of solute × 1000/ (Molar mass of solute × Volume of solution in mL). It is given that M=0.4 and V= 500mL. By putting the values in formula we get: 0.4=Mass of NaOH ×1000/ (40×500). WebMar 17, 2024 · As indicated by the given chemical equation, one mole of NaOH reacts with one mole of KHP; thus, the amount of KHP that reacted is also equal to 0.0014101 moles. Using the molecular weight of KHP (204.2 g/mol), we can conclude that about 0.28794 g of KHP reacted and became NaKP.
MLT 211 Calculations Of Solutions Flashcards Quizlet
WebTo simply calculate the amount or weight of a substance needed for a desired molar solution, the following formula may be used: Weight in grams = desired molarity x volume needed in liters x GMW -- OR -- (W = M x V x GMW) Example: 500 mL of a 0.1M solution of NaOH is needed for a procedure. Web(GMW = 40) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Question: 5. How would you prepare a 2M solution of NaOH? (GMW = 40) 5. How would you prepare a 2M solution of NaOH? (GMW = 40) Expert Answer 100% (1 rating) Hope … View the full answer simonmed 107th ave mcdowell
What is the percentage of KHP in the mixture? - Wyzant
Web(GMW: 40g/mol). 2) How would you prepang 200ml of 0.4M NaOH from solid NaOH. (GMW: 40g/mol). 3) If given 10ml of vinegar and vold that 23ml of 4M KaOH was used to reach the end point during a titration: CH3COOH .NOH → Na+CIyC00. +HsO A) Calculate the moles of Acethe Acid. (GMW: Show transcribed image text Expert Answer Transcribed image text: WebSolution): Mass of KHP used: Initial volume of NaOH: Final volume of NaOH at end-point: Total volume of NaOH titrated = Initial volume of NaOH - Final volume of NaOH at end-point = Moles of KHP = Moles of NaOH at end point Moles of KHP = Mass of KHP/GMW of KHP (=204.2) = 2/204.2 = .00979 Molarity of NaOH = Moles of KHP/volume of NaOH titrated … WebQuestion: QUESTION 4 What is the molarity of an aqueous solution of 25.0 g of NaOH (use molar mass of sodium hydroxide = 40 g/moe) in 250 ml? a. 1.0 mol/L b. 0.625 mol/L OC. 2.5 mol/L d. 0.25 mol/L e. 1.25 mol/L This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer simonmed 13657 west mcdowell